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Otter@lemmy.ca to No Stupid Questions@lemmy.worldEnglish ·
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4 days ago

What strategy would you use to estimate the number of hazelnuts

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What strategy would you use to estimate the number of hazelnuts

media.piefed.social

Otter@lemmy.ca to No Stupid Questions@lemmy.worldEnglish ·
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4 days ago
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For some of these, I estimate the number of items the base and then multiply by the height. Is there a better strategy, especially for items that don’t fit into distinct layers?

Original post crossposted from !dailygames@lemmy.zip: https://piefed.social/post/1205620

Guess here: 🔗 https://estimate-me.aukspot.com/archive/2025-08-29

If you’d like to discuss your guesses, please use spoiler tags!

  • m0darn@lemmy.ca
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    4 days ago

    I did

    V=pi×r²×h

    and estimated:

    r=4 (from some at the top left)

    h=12

    This gave 603. The link said too high, so realized I’d neglected packing factor. Google said that spheres typically pack at 64% efficiency, so I guessed 386. Too low.

    • Disaffected Scorpio@lemmy.world
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      4 days ago

      These aren’t spheres, though, so the packing efficiency could be better, like 72% or better. These look better packed than those vases filled with glass marbles. So it could even be in the 80s.

      • m0darn@lemmy.ca
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        4 days ago

        Yeah I went 80% next which was too high. 72% is very close to the answer in the link.

    • aeiou_ckr@lemmy.world
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      4 days ago

      Is there a name for this equation ands can you explain the pix part of the equation?

      • abbadon420@sh.itjust.works
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        4 days ago

        Its not “pix” its “pi * r² * h”. It’s a basic equation for the volume (V) of a cylinder.

        • aeiou_ckr@lemmy.world
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          3 days ago

          Gotcha, thanks.

      • stormdelay@sh.itjust.works
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        4 days ago

        It’s the volume of a cylinder, pi times height times radius squared

        • aeiou_ckr@lemmy.world
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          3 days ago

          Oh. Thanks. :)

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